SOLUTION: I have a proof which I have almost completed but I am missing a step and not sure which one it is. Here's the scenario: EG bisects angle EDF (given) angle EDF = EFG (given)

Question 824279: I have a proof which I have almost completed but I am missing a step and not sure which one it is. Here's the scenario:
EG bisects angle EDF (given)
angle EDF = EFG (given)
I have correctly made the first steps:
EG = EG reflexive property
missing step??
triangle DEG = triangle FEG AAS
DG = FG CPCTC
triangle DGF is isoceles Definition of isoceles
I need some help figuring this portion out please, would the correct answer be:
EG = DGF?

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
With the "givens" that you list, there is no way to prove anything.

To be able to prove that triangle DGF is isoceles,
you need to be given angle EDG = EFG,
not angle EDF = EFG as you wrote.
I assume that was a typo.
With angle EDG = EFG given, to use AAS,
you need to state that another pair of angles are congruent.
It may seem very obvious to you that, once you bisect angle EDF with EG,
you have split it into two congruent angles, but you still have to state it as
angle DEG = angle FEG (definition of angle bisector)
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