SOLUTION: Given: BM⊥AC , M is the midpoint of AC. Prove: ΔABM ≅ ΔCBM. Has to be written as Statements & Reasons. I really want to know how to do this!

Question 762957: Given: BM⊥AC , M is the midpoint of AC.
Prove: ΔABM ≅ ΔCBM.
Has to be written as Statements & Reasons. I really want to know how to do this!
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!
This can be proved using the SAS (Side-Angle-Side) theorem, which is: If two corresponding sides, and the included angle, of 2 triangles are equal, then the 2 triangles are congruent.
If you compare triangles ABM and CBM,
Side MB is common to both.
AM = MC since M is the midpoint.
Angle AMB = angle BMC = 90, since BM is perpendicular to AC.
Hence 2 sides and the included angle are equal. So triangles ABM and CBM are congruent.
Hope this helps :)

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SOLUTION: Given: BM&#8869;AC , M is the midpoint of AC. Prove: &#916;ABM &#8773; &#916;CBM. Has to be written as Statements & Reasons. I really want to know how to do this!

SOLUTION: Given: BM⊥AC , M is the midpoint of AC. Prove: ΔABM ≅ ΔCBM. Has to be written as Statements & Reasons. I really want to know how to do this!