SOLUTION: ABCD is a trapezium. The two diagonal AC and BD intersect in O. extended DA and CB intersect in P. prove that OP is the bisector of AB.

Algebra.Com
Question 730283: ABCD is a trapezium. The two diagonal AC and BD intersect in O. extended DA and CB intersect in P. prove that OP is the bisector of AB.
Answer by lynnlo(4176)   (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS

ABCD is a trapezium in which AB is parallel to DC. The bisectors of angles A and D... (answered by greenestamps)
In the given figure pqrs is a parallelogram and the diagonal intersect at o if op= 2.5 cm (answered by solver91311)
In the trapezium OABC, OA = a, OC = c and CB = 3a. T is the point on BC such that BT: TC (answered by ikleyn)
Diagonals AC and BD of a parallelogram ABCD intersect at O . Given that AB=12 gm and the... (answered by ikleyn)
.Trapezoid ABCD has parallel sides AB and CD, of lengths 12 and 18, respectively.... (answered by greenestamps)
I have a proof and shown is quadrilateral ABCD. On the figure the diagonals AC and DB are (answered by solver91311)
I do not understand proofs or in what order to put the statements according to the... (answered by mananth)
In a trapezoid ABCD with legs AB and CD, the diagonals intersect each other at point O. (answered by MathLover1)
In trapezoid ABCD, diagonals AC,BD intersect at M. AD is parallel to BC and MN. AD=3,... (answered by ikleyn)