You can
put this solution on YOUR website!Given that the decay rate = 1.5%
So half life = ln(2)/0.015
= 0.6932/0.015
= 46.2
Thus the isotope has a half life of 46.2 yrs
which means that the isotope would reduce to half its initial value in 46.2 yrs with the decay rate being 1.5%
Good Luck!!!