SOLUTION: Let ABCD be a trapezoid with parallel bases AD and BC. The diagonals meet at O. Prove that AO/CO=OD/BO

Question 592225: Let ABCD be a trapezoid with parallel bases AD and BC. The diagonals meet at O.
Prove that AO/CO=OD/BO
Found 2 solutions by 253689, ikleyn:
Answer by 253689(1) (Show Source): You can put this solution on YOUR website!
12
Answer by ikleyn(52898) (Show Source): You can put this solution on YOUR website!
.
It is so because the triangles AOB and COD are similar.

(The vertices of the triangles are listen in the corresponding order).

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