SOLUTION: Find two consecutive numbers such that the sum of their squares is 35 more than twice the square of the smaller.

SOLUTION: Find two consecutive numbers such that the sum of their squares is 35 more than twice the square of the smaller.

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Question 54440: Find two consecutive numbers such that the sum of their squares is 35 more than twice the square of the smaller.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Try this:
Let x be the smaller number, then x+1 will be the next consecutive number.
Simplify and solve for x.

Subtract 2x^2 from both sides.
Subtract 1 from both sides.
Finally, divide both sides by 2.
and
Check:
= 613
= 613

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