# SOLUTION: I have been given the following problem and can't seem to figure out the answer: You are given triangle abc, and and abc in that triangle is a right angle. You are also given p

Algebra ->  Algebra  -> Geometry-proofs -> SOLUTION: I have been given the following problem and can't seem to figure out the answer: You are given triangle abc, and and abc in that triangle is a right angle. You are also given p      Log On

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 Geometry: Proofs in Geometry Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Geometry proofs Question 41417: I have been given the following problem and can't seem to figure out the answer: You are given triangle abc, and and abc in that triangle is a right angle. You are also given pqrs is a rectangle inside the triangle, so that ps is parallel to ab. This problem is trying to prove that (PQ) squared is equal to AQ x BRAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!I have been given the following problem and can't seem to figure out the answer: You are given triangle abc, and and abc NO NOT CORRECT ACB IS THE RIGHT ANGLE. in that triangle is a right angle. You are also given pqrs is a rectangle inside the triangle, so that ps is parallel to ab. This problem is trying to prove that (PQ) squared is equal to AQ x BR HOPE YOU GOT THE FIGURE WITH YOU...P IS AC,S IS ON BC AND Q & R ARE ON AB. ANGLE ACB=90,OTHER ANGLES ARE A AND B PS IS || TO AB...GIVEN BC IS TRANVERSAL HENCE ANGLE CSP=ANGLE CBA=B.........CORRESPONDING ANGLES PCS IS RIGHT ANGLED TRIANGLE AT C .HENCE ANGLE CPS =90-ANGLE CSP =90-B ANGLE APQ + ANGLE QPS + ANGLE CPS =180 ANGLE APQ =180-90-(90-B)=180-90-90+B=B HENCE IN TRIANGLES APQ AND SBR,WE HAVE ANGLE APQ =B = ANGLE SBR...PROVED ABOVE ANGLE AQP=90=ANGLE SRB...PQRS IS A RECTANGLE HENCE THE 2 TRIANGLES ARE SIMILAR SO AQ/SR=PQ/BR BUT PQ=SR .....PQRS IS RECTANGLE SO AQ/PQ=PQ/BR AQ*BR=PQ^2