SOLUTION: if AC=DB and AC and DB bisect each other at E, then AE=EB
Algebra.Com
Question 356581: if AC=DB and AC and DB bisect each other at E, then AE=EB
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let x = ac = db. Since ac and db bisect each other at e, then e is the midpoint both of ac and db. Hence each of ae and eb will have length equal to x/2, and thus ac = db.
RELATED QUESTIONS
AC and DE bisect each other
If AB = 2x – 3, DB = x + 5, and BC = x + 3, what is the (answered by ewatrrr)
Given:
square ABCD with diagonals DB and AC intersecting at E
DC = 8radical 3
Find:... (answered by mananth)
Given:
rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E
DB = (answered by mananth)
Given:
square ABCD with diagonals DB and AC intersecting at E
DC = 8radical 3
Find:... (answered by josgarithmetic)
Rhombus named ABCD with a diagonals AC and DB. Given: AC = 18 and DB = 8
Find:
AE
DE
(answered by MathLover1)
Given: rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E
DB =... (answered by Boreal)
Given:
rhombus ABCD (not shown) in which diagonals AC and DB intersect at point E
DB = (answered by josgarithmetic,ikleyn)
if ad=3 and db=24, find... (answered by Alan3354)
Given:
square ABCD with diagonals DB and AC intersecting at E
DC = 8radical 3
Find:DB (answered by Boreal)