SOLUTION: Two parallel chords each have length 12, and the distance between them is 8. What is the radius of the circle.

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Question 325100: Two parallel chords each have length 12, and the distance between them is 8. What is the radius of the circle.
Found 3 solutions by mananth, ankor@dixie-net.com, Fombitz:
Answer by mananth(16946)   (Show Source):
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the chords are 12cm apart.
'
A perpendicular drawn from the center to the chord bisects the chord and the centre is equidistant from both the chords.
perpendicular distance from chord to centre = 4
half the chord = 6
The perpendicualr distance , half the chord and radius form a right triangle. with radius as the chord.
6^2+4^2= radius ^2
36+16=radius^2
sqrt52=radius

Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
Two parallel chords each have length 12, and the distance between them is 8.
What is the radius of the circle.
:
Parallel chords of equal length are the same distance from center
Therefore they are 4 units from center
:
A right triangle is formed by dist to center (4) and half the chord length (6)
The hypotenuse of this triangle is the radius, therefore
:
r =
r =
:
r = 7.21 is the radius

Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website!

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As you see from the diagram,