SOLUTION: a right triangle is drawn where the right angle is on the top..
Given: triangle ABC, <ACB is a right angle, and CD is perpendicular to AB.
Prove: AC x BD = CD x BC
..
s
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Given: triangle ABC, <ACB is a right angle, and CD is perpendicular to AB.
Prove: AC x BD = CD x BC
..
s
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Question 196690: a right triangle is drawn where the right angle is on the top..
Given: triangle ABC,
Prove: AC x BD = CD x BC
..
so i understand that the relation of it would be hypotenuse to leg = hypotenuse to leg .. i just don't understand how to solve it since there's no numbers. thank you! Answer by solver91311(5072) (Show Source):
