(1) ~C \/ D (2) (~A \/ B) -> F (3) ~B -> C (4) ~F Prove: D I. ~F Given II. ~(~A/\~B) By ~F -> ~(~A\/B), the contrapositive of (2) III. ~(~A)/\~B ~(~A\/B) <-> ~(~A)/\~B DeMorgan's law IV. A/\~B ~(~A)<-> A Negation of negation V. ~B Conjunction IV VI. C V, and (3), ~B -> C is given VII. ~C \/ D given VIII. C /\ (~C \/ D) Conjunction of VI with VII IX. (C /\ ~C) \/ (C /\ D) Distributive law with VIII X. false \/ (C /\ D) Conjunction of C with its negation is false XI. C /\ D "false" is the identity for disjunction XII. D Conjunction XI Edwin