You can
put this solution on YOUR website!Let x=measure of exterior angle and y = measure of interior angle
We know that the formula for the interior angle is
So in this case
Also, remember that

since the sum of the interior and exterior angle is 180

Solve for "y"

Plug in

Multiply EVERY term by "n" to clear the fraction

Distribute

Subtract 180n from both sides.

Divide both sides by -n to isolate x (which is the exterior angle)

Reduce
So this shows that for any regular n-gon, the exterior angle will be
You can
put this solution on YOUR website!prove that one exterior angle of the polygon is 360/n.
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sum of the interior angles of a polygon is given by the equation sum of i = (n-2)*180.
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since a polygon of n sides has n interior angles, then each interior angle measures ((n-2)*180)/n so the formula for an interior angle is
i = ((n-2)*180)/n
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each exterior angle is a supplement of each interior angle, so each exterior angle measure 180 - ((n-2)*180)/n) so the formula for an exterior angle is
e = 180 - ((n-2)*180)/n)
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multiplying both sides of the equation by n we get
n*e = n*(180-((n-2)*180)/n)
which becomes
n*e = 180*n - (180*n - 360)
removing parentheses this equation becomes
n*e = 180*n - 180*n + 360)
combining like terms this becomes
n*e = 360
dividing both sides of the equation by n make it
e = 360/n
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