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A regular hexagon has a perimeter of p (in length units) and an area of A (in square units).
If A=3/2 then find the side length of the hexagon.
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As I read this post by @CPhill, it saddens me to see how clumsily the problem is formulated
and how poorly the solution is presented.
The part " hexagon has a perimeter of p " is totally irrelevant to the problem and should be omitted.
The normal formulation to this problem is as follow
A regular hexagon has the area of 3/2 square units.
Find the side length of the hexagon.
Below is a normal mathematical solution in a form as it should be.
Let 'a' be the side length of the regular hexagon.
This hexagon is the union of 6 equilateral triangles with the side length of 'a'.
So, the area of each such a triangle is = of the square unit.
The area of each such a triangle is .
So, for 'a' we have this equation
= ,
which implies
= ,
a = = 3^(-1/4) = 0.7598 (rounded).
ANSWER. The side of the regular hexagon is a = = 3^(-1/4) = 0.7598 (rounded).
CHECK. = 1.49986 for the full area, which is a good approximation.
Solved.
Compare this solution with the mess of words in the post by @CPhill.