SOLUTION: show that if A-B-C and B-C-D,then A-B-D and A-C-D

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Question 1200959: show that if A-B-C and B-C-D,then A-B-D and A-C-D
Found 3 solutions by Edwin McCravy, ikleyn, greenestamps:
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
Now let's get this straight.  Your problem is:
show that if A-B-C and B-C-D,then A-B-D and A-C-D
That doesn't make any sense, as I told you before.

Suppose A=7, B=3, C=2, D=1.

A-B-C = 7-3-2 = 2  
B-C-D = 3-2-1 = 0
A-B-D = 7-3-1 = 3
A-C-D = 7-2-1 = 4

Let's substitute those values in what you wrote, which was:
show that if A-B-C and B-C-D,then A-B-D and A-C-D
We get:
show that if 2 and 0,then 3 and 4
Do you think that makes any sense?  If so, you are the only
person on the planet who thinks it does.

Edwin
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.

Edwin,

I think, it is not about arithmetic operations - - - it is about logical implications.



Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


As you can see, two other tutors have different guesses as to what this problem is about.

Since the topic is "geometry proofs", my guess is that the question is about ordering of points on a line segment.

So that's three different interpretations of your post. That should tell you that posting your problem the way you did is a waste of your time and ours....

When you make a post, remember that we know nothing about the problem except what you show us. If you want help with your question, take the time to make your post in a way that we know what your question is.

Re-post your question... clearly.
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