SOLUTION: Prove triangle xyz = 1/7 triangle ABC, where triangle xyz is formed by three segments between the vertices and the one third of the opposite sides of the triangle ABC.

Question 1179629: Prove triangle xyz = 1/7 triangle ABC, where triangle xyz is formed by three segments between the vertices and the one third of the opposite sides of the triangle ABC.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13209) (Show Source): You can put this solution on YOUR website!

Poor grammar and no discernible relationship between triangles ABC and XYZ.

Re-post so we don't have to guess what the question is.

Answer by ikleyn(52880) (Show Source): You can put this solution on YOUR website!
.

This theorem of Geometry is called "One-seventh area triangle".

It is FAR ABOVE elementary school geometry curriculum.

About this theorem, see these links

https://en.wikipedia.org/wiki/One-seventh_area_triangle

https://en.wikipedia.org/wiki/Routh%27s_theorem

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