(1) Connect the centers X and Y by the segment XY. Let C be the intersection point of segments XY and AB. Notice that AC = BC = half of AB = 24/2 = 12 cm (2) Then XAC is the right triangle. Its leg XC is= = = 16 cm. (3) Similarly, YAC is the right triangle. Its leg YC is = = = 9 cm. (4) Now the length of the segment XY is 16+9 = 25 cm. ANSWER. The distance between the centers is 25 cm.