SOLUTION: two-column proof
Given: AD is a diameter of ⊙ O;
Dc is tangent to ⊙ O at D.
Prove: ∆ABD ~ ∆ADC
(link to image)
https://photos.google.com/share/AF1QipP8NZbitIdE4if7
Algebra.Com
Question 1154892: two-column proof
Given: AD is a diameter of ⊙ O;
Dc is tangent to ⊙ O at D.
Prove: ∆ABD ~ ∆ADC
(link to image)
https://photos.google.com/share/AF1QipP8NZbitIdE4if7gv7lYYeUYvKSWEISM6Qgmxd2lzXcd4Ch0c2RSDOxHLLT5-f7MA/photo/AF1QipNXVz3UAGa3sqxTDM5NKDI9-Vy_ev9eEbUQadKe?key=dVg4TjFJTEV6OWE2clkxYl8wT25OTFRpUW92UWpB
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
consider the triangles
∆ABD ~ ∆ADC
There fore ∆ABD ~ ∆ADC. By angle angle test of similarity
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