SOLUTION: In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD = °.

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Question 1153816: In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD =
°.
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20855)   (Show Source): You can put this solution on YOUR website!

The of a parallelogram .

so, angles and are opposite angles
if m< °, m < °
Answer by ikleyn(53763)   (Show Source): You can put this solution on YOUR website!
.

            Tutor @MathLover1 is trying to solve the problem,  even without reading it,  so,  she is  WRONG. 


In triangle ABD, you are given two angles, ABD and BDA.


Their sum is 83° + 34° = 117°.


Angle A (same as angle DAB) is, therefore, the supplementary angle to 117°,

so the measure of the angle DAB is 180° - 117° = 63°.


Angle  BCD is the opposite angle in parallelogram ABCD to the angle DAB, so its measure is 63°.    ANSWER


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