SOLUTION: For indirect proofs, how can I prove that point O lies on line AD with the givens: Circle O with AB congruent to AC, and line AD is the median to BC with the usage of equidistance

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Question 1148981: For indirect proofs, how can I prove that point O lies on line AD with the givens: Circle O with AB congruent to AC, and line AD is the median to BC with the usage of equidistance theorems? I realized that triangle ADB and ABC are congruent by the SSS postulate, that I may need to draw lines OB and OC, and AD would be a perpendicular bisector of BC. However, I am not certain on how I can use this or if my assumptions are even accurate.
Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!


Your description of the given information is not sufficient for us to know exactly what the picture is; so there is no point in our trying to help you with your question.

Re-post with a complete description; or post a diagram to any of a number of free hosting sites and include the URL for the diagram in your post.
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