SOLUTION: Show that the side of a rectangle whose area is 100 meter^2 with minimum perimeter is 10 meter

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Question 1148244: Show that the side of a rectangle whose area is 100 meter^2 with minimum perimeter is 10 meter
Answer by ikleyn(52880)   (Show Source): You can put this solution on YOUR website!
.

They want you to prove that

    if  x and y are two positive real numbers whose product is 100,  x*y = 100, 

    then the the minimum value of x+y is achieved at x = y = 10.

It is simple calculus problem.


Solution

If x*y = 100,  then  y = ,  and the sum  x+y  is  x + .


This function of "x",  f(x) = x +   achieves the minimum when its derivative is equal to zero


    f'(x) = 1 -  = 0.


Then    = 100;  hence  x =  = 10.


Thus we proved that if  x*y = 100,  then  x+y has minimum at  x = y = 10.

Solved.


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