1. Make a sketch. 2. Let C be the point where the two small circles touch each other. Let |AC| = x (the unknown length - same as the radius of each of the two small circles). Then |BC| = x, too. |AO| = r-x and |BO| = r-x (OBVIOUS. Use the sketch) The perimeter of the triangle AOB is equal to |AO| + |BO| + |AC| + | BC| = (r-x) + (r-x) + x + x = 2r.