Lesson How Functions Can Work

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This Lesson (How Functions Can Work) was created by by Nate(3495) About Me : View Source, Show
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Lets start with the basic linear function.
f(x) = x
graph(300,300,-5,5,-5,5,x)
f(x) = x + 1 wouldn't you easily think that all points would increase one (so vertically shifts one unit)
graph(300,300,-5,5,-5,5,x+1)
f(x) = 2x + 1 you could easily understand that the slope is affected (the slope is steeper)
graph(300,300,-5,5,-5,5,2x+1)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Now, lets use a parabolic function.
f(x) = (x)^2
graph(300,300,-5,5,-5,5,(x)^2)
f(x) = (x - 1)^2 knowing: f(x) = a(x - h)^2 + k where (h,k) is the vertex, the x-value is shifted -h units, parabola shifts one unit to the right
graph(300,300,-5,5,-5,5,(x - 1)^2)
f(x) = (x - 1)^2 + 2 whenever you add to a function like this, all the units shift vertically (graph shifts two units vertically)
graph(300,300,-5,5,-5,5,(x - 1)^2 + 2)
f(x) = (2)(x - 1)^2 + 2 the value of a determines the contractions of the parabola (the parabola bends in 2x)
graph(300,300,-5,5,-5,5,2(x - 1)^2 + 2)
f(x) = (2)(2x - 1)^2 + 2 further bending of the parabola, but distorts the vertex
graph(300,300,-5,5,-5,5,2(2x - 1)^2 + 2)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Now, lets use a trig function.
f(x) = sin(x)
graph(300,300,-5,5,-5,5,sin(x))
f(x) = sin(x + 1) works the same, all values shifts -1 units horizontally
graph(300,300,-5,5,-5,5,sin(x+1))
f(x) = sin(x + 1) + 1 just like the parabola, the 'wave' is vertically shifted one unit
graph(300,300,-5,5,-5,5,sin(x + 1) + 1,1)
f(x) = 2sin(x + 1) + 1 unlike the parabola, this value determines the height of the 'wave'
graph(300,300,-5,5,-5,5,2*sin(x + 1) + 1,1)
f(x) = 2sin(2x + 1) + 1 the coefficient determines the frequency (2pi/c) ~> where c is the coefficient ~> (frequency = pi)
graph(300,300,-5,5,-5,5,2*sin(2x + 1) + 1,1)

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