SOLUTION: f(x)= 〖2x〗^2-16x+30 , g(x)= 〖x(x-3)〗^2 〖(x+1)〗^4 Find the zeros of g(x)and f(x)

Algebra.Com
Question 999894: f(x)= 〖2x〗^2-16x+30 ,
g(x)= 〖x(x-3)〗^2 〖(x+1)〗^4
Find the zeros of g(x)and f(x)

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
f(x)=4x^2-16x+30
x=(1/8)(16+/- sqrt (256-480). The square root is negative. There are no zeros.


x(x-3)〗^2 〖(x+1)〗^4
Either of the two must equal zero
x=0, x=3, x=-1

RELATED QUESTIONS

Given f(x)= 〖2x〗^2-16x+30 , g(x)= 〖x(x-3)〗^2... (answered by stanbon)
Solve (a) 〖 4〗^x=8, (b) 〖... (answered by stanbon)
Help to solve this equation: 〖log〗_10 x+ 〖log〗_10 2=... (answered by stanbon)
Prove that 〖 lim┬(x→-4) 〗⁡〖x^2=16... (answered by lynnlo)
Verify the identity sinx(cscx+sinx〖sec〗^2 x)=〖sec〗^2... (answered by MathLover1)
〖(x-5)〗^2=16 (answered by Fombitz)
a. Is the point (-1, 1) on the graph of... (answered by macston)
solve for x: 〖log〗_2 x=〖log〗_2... (answered by nerdybill)
solve for x: 〖log〗_2 x=〖log〗_4... (answered by jsmallt9)