SOLUTION: Please Help. Let {{{f(x)=2x^2-2x}}}
Simplify {{{(f(x+h)-f(x))/h}}}
Answer: 4x+2h-2
But how? I have tried:
{{{(fx+fh)-f(x))/(h)}}}
{{{((2x^2-2x)+fh-(2x^2-2x))/h}}}
{{{((2
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-> SOLUTION: Please Help. Let {{{f(x)=2x^2-2x}}}
Simplify {{{(f(x+h)-f(x))/h}}}
Answer: 4x+2h-2
But how? I have tried:
{{{(fx+fh)-f(x))/(h)}}}
{{{((2x^2-2x)+fh-(2x^2-2x))/h}}}
{{{((2
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Question 981953: Please Help. Let
Simplify
Answer: 4x+2h-2
But how? I have tried: Found 3 solutions by josgarithmetic, Edwin McCravy, AnlytcPhil:Answer by josgarithmetic(39618) (Show Source):
You can put this solution on YOUR website! You substituted the wrong expression. Try building each part separately before making the substitution into the formula.
, which already is given.
, the initial input for the function.
Can you take this the rest of the way, into the difference quotient and simplifications... to a final result?
You are thinking that f(x) means f times x.
Please get rid of that idea now. f(x) does NOT mean f times x.
The (x) is just a place holder for whatever is going to be
substited for x on the right side of the equation.
Here's an example just like yours that you can go be as a model:
Simplify .
Do it in stages. Find f(x+h), then f(x+h)-f(x), then .
First find f(x+h
So
and since
So
Then finally find
we divide that by h:
So
Edwin