SOLUTION: A field is being built that has an area of 1000 square yards. The field must be 30 yards longer than its width. Determine algebraically the dimensions of the soccer field in yards

Question 981345: A field is being built that has an area of 1000 square yards. The field must be 30 yards longer than its width. Determine algebraically the dimensions of the soccer field in yards
Found 2 solutions by solver91311, macston:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Solve for

John

My calculator said it, I believe it, that settles it

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
A=Area=1000yd^2; L=length; W=width=L-30yds
.
A=LW
1000yds^2=(L)(L-30yds)
1000yds^2=L^2-30L
0=L^2-30L-1000
0=(L-50)(L+20)
L-50=0 OR L+20=0
L=50 yards OR L=-20 yards
ANSWER 1: The length of the field is 50 yards.
W=L-30yds=50yds-30yds=20yds ANSWER 2: The width of the field is 20 yards.
.
The field is 50 yards by 20 yards.
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