SOLUTION: n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1
A. SQRT(3^x) + 1
B. 3[SQRT(t)]
C. SQRT(t) + 3
D. 3[SQRT(t) + 1]
E. 3[SQRT(t)] + 3
F. SQRT(3^x) + 3
Algebra.Com
Question 980055: n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1
A. SQRT(3^x) + 1
B. 3[SQRT(t)]
C. SQRT(t) + 3
D. 3[SQRT(t) + 1]
E. 3[SQRT(t)] + 3
F. SQRT(3^x) + 3
Answer by josh_jordan(263) (Show Source): You can put this solution on YOUR website!
To solve, you would insert the value of into the x in 3^x. So, the answer would be
Answer: D
RELATED QUESTIONS
n[m(t)] if n(x) = 3x and m(t) = SQRT(t) + 1
A SQRT(3x) + 1
B3[SQRT(t)]
CSQRT(t) + (answered by stanbon)
n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1
m[n(x)] if n(x) = 3x and m(t) = SQRT(t) + (answered by tommyt3rd)
m[n(x)] if n(x) = 3^x and m(t) = SQRT(t) + 1
(answered by tommyt3rd)
Again, functions!
n(x)=3^x m(t)=SQRT(t)+1 find n(m(t))
My answer was... (answered by RAY100,drj)
n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1
I really need some help I'm not... (answered by Fombitz)
I seem to have a problem with functions!
n(x)=3^x m(t)=SQRT(t)+1 find m(n(x))
(answered by Earlsdon,Theo)
Given that f(x) = sqrt (3-x) , find f(m + 2).
A) sqrt (1-m)
B) sqrt (m+2-x)
C)... (answered by checkley77)
the values for x(3pi/2) and y(3pi/2) for x(t)=cos(t),y(t)=sin(t) are
A)(0,-1)
B)(.5,... (answered by Theo)
sqrt(t+3+7=9 then... (answered by Fombitz)