SOLUTION: n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1 A. SQRT(3^x) + 1 B. 3[SQRT(t)] C. SQRT(t) + 3 D. 3[SQRT(t) + 1] E. 3[SQRT(t)] + 3 F. SQRT(3^x) + 3

Algebra.Com
Question 980055: n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1
A. SQRT(3^x) + 1
B. 3[SQRT(t)]
C. SQRT(t) + 3
D. 3[SQRT(t) + 1]
E. 3[SQRT(t)] + 3
F. SQRT(3^x) + 3

Answer by josh_jordan(263)   (Show Source): You can put this solution on YOUR website!
To solve, you would insert the value of into the x in 3^x. So, the answer would be

Answer: D

RELATED QUESTIONS

n[m(t)] if n(x) = 3x and m(t) = SQRT(t) + 1 A SQRT(3x) + 1 B3[SQRT(t)] CSQRT(t) + (answered by stanbon)
n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1 m[n(x)] if n(x) = 3x and m(t) = SQRT(t) + (answered by tommyt3rd)
m[n(x)] if n(x) = 3^x and m(t) = SQRT(t) + 1 (answered by tommyt3rd)
Again, functions! n(x)=3^x m(t)=SQRT(t)+1 find n(m(t)) My answer was... (answered by RAY100,drj)
n[m(t)] if n(x) = 3^x and m(t) = SQRT(t) + 1 I really need some help I'm not... (answered by Fombitz)
I seem to have a problem with functions! n(x)=3^x m(t)=SQRT(t)+1 find m(n(x)) (answered by Earlsdon,Theo)
Given that f(x) = sqrt (3-x) , find f(m + 2). A) sqrt (1-m) B) sqrt (m+2-x) C)... (answered by checkley77)
the values for x(3pi/2) and y(3pi/2) for x(t)=cos(t),y(t)=sin(t) are A)(0,-1) B)(.5,... (answered by Theo)
sqrt(t+3+7=9 then... (answered by Fombitz)