SOLUTION: I didn't know category to put under so I decided to put under functions, but it's more of a reducing thing. I've been trying to solve the following: Find f�g�h f(x)= x^1/2,

Question 974846: I didn't know category to put under so I decided to put under functions, but it's more of a reducing thing.
I've been trying to solve the following:
Find f�g�h
f(x)= x^1/2, g(x)= x/(x-6), h(x)= x^1/9
I know how to do it - f(g(h(x))) - but I can't seem to get it down to lowest terms.
This is what I got so far:
[x^1/9/(x^1/9 - 6)]^1/2
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

You can't get much simpler than

The only thing there is to try with this is to rationalize the denominator, and that path gets you nowhere.

Depending on what computations or processes that you intend after this point, you might want to leave it with fractional exponents throughout,

Or perhaps organize a campus protest against ugliness in mathematics.

John

My calculator said it, I believe it, that settles it

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