SOLUTION: Find the vertical asymptote(s) and/or holes for R(x)=4/(x² -25)(x+2).
I have the vertical asymptotes as x=5,x=-5 and x=2. Is this correct? As for holes I am lost, haha,
Algebra.Com
Question 953557: Find the vertical asymptote(s) and/or holes for R(x)=4/(x² -25)(x+2).
I have the vertical asymptotes as x=5,x=-5 and x=2. Is this correct? As for holes I am lost, haha,
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
What, this? R(x)=4/((x² -25)(x+2))
Trying to render, AMP Parsing Error of [R(x)=4/((x² -25)(x+2))]: Invalid expression. Closing bracket expected ²-25)(x+2)) at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187.
.
Do you mean this?
Vertical asymptotes are x=5, x=-5, x=-2.
Factors of the denominator do not occur in the numerator, so no holes.
Finding your way: is equivalent to .
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