SOLUTION: Finding the vertex and x and y intercepts of: G(t)=1/2(t^2-4t)? I know I can turn this into vertex form like so: G(t)=1/2(t^2-4t+4)-4 G(t)=1/2(t-2)^2-4 so then the vertex

Question 948282: Finding the vertex and x and y intercepts of: G(t)=1/2(t^2-4t)?
I know I can turn this into vertex form like so:
G(t)=1/2(t^2-4t+4)-4
G(t)=1/2(t-2)^2-4
so then the vertex would be
(2,-4) but graphing it online it states that the vertex is:(2,-2) what am I missing here? what makes it a -2 instead of a -4?
Please also explain how to find the x and y intercepts thank you
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
When you added the 4 in the parentheses, you were really adding .
Well you subtracted 4 but it should have been 2.
So,

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.
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X-intercepts: Set solve for .

So then and are the x-intercepts (or the t-intercepts).
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Y-intercept : Set solve for .

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