SOLUTION: Can you please explain why the domain of f(x)=(x-2)^2 is all real numbers? my calculations were
f(x)=(x-2)^2
(x-2)(x-2)
x=2 therefore the domin cannot be postive 2 so (-∞
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Question 945931: Can you please explain why the domain of f(x)=(x-2)^2 is all real numbers? my calculations were
f(x)=(x-2)^2
(x-2)(x-2)
x=2 therefore the domin cannot be postive 2 so (-∞,2)U(2,∞) wouldn't this exclude the 2's and therefore it wouldn't be all real numbers?
Thanks
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Can you please explain why the domain of f(x)=(x-2)^2 is all real numbers? my calculations were
f(x)=(x-2)^2
(x-2)(x-2)
x=2 therefore the domin cannot be postive 2 so (-∞,2)U(2,∞) wouldn't this exclude the 2's and therefore it wouldn't be all real numbers?
===========
x = +2 --> f(x) = 0
No reason to exclude it.
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