SOLUTION: The function f:x->px+q, xER, is such that f^-1 (6)=3 and f^-1 (29)=-2. Find f^-1 (27). I have spent a long time trying to figure this out and I can't get it. The answer giv

Question 941055: The function f:x->px+q, xER, is such that f^-1 (6)=3 and f^-1 (29)=-2.
Find f^-1 (27).
I have spent a long time trying to figure this out and I can't get it.
The answer given in the textbook is 6.
I have found the inverse function to be f^(-1): 1/p (x-q) so I am guessing that means I subtract or add something to x and then divide it.
Any help on this would be greatly appreciated.
Thanks
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
so
so

1.
2.
Subtract eq. 1 from eq. 2,

Then use either equation to solve for

So then,

.
.
.
The answer of doesn't make sense.
Since the solution is linear and is between and , the solution needs to be between and , closer to since is closer to . My solution is about , close compared to . is not even in the possible range of solutions.

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