You can
put this solution on YOUR website!state the domain...I think I have it...maybe
f(x) = sqrt(x+4)
x=4 must be >=0
x must be >= -4
Domain: all Real Numbers >=-4
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g(x) = 2x+1/x-3
The denominator must not be zero.
Domain: all Real Numbers except x=3
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l(x) = 2x + 3
Domain: all real numbers
That's correct.
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m(x) = 3/(x^2 + 7)
The denominator must not be zero.
It never is because x^2 >=0 so x^2+7>=7.
Domain: all Real Numbers
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Cheers,
Stan H.
You can
put this solution on YOUR website!
Set the radicand (everything in the square root) greater than zero (remember you cannot take the square root of a negative number)
Subtract 4 from both sides
So the domain is x can be any number greater than -4
Set the denominator equal to zero
Add 3 to both sides. So x=3 is excluded from the domain since it makes the denominator equal to zero
So x can be any number except 3
you are correct, x can be any real number
l(x) = 2x + 3
you are correct, x can be any real number
Set the denominator equal to zero
Subtract 7 from both sides
Since you cannot take the square root of a negative and get a real answer, there are no values of x that will make
equal zero. So the domain is x is an element of all real numbers
(