SOLUTION: Find the inverse function of y = √(x^2-5x-6) I have tried doing: x = √(y^2-5y-6) x^2 = y^2-5y-6.......and couldn't isolate y from here. Thank-you for your time!

Question 919876: Find the inverse function of y = √(x^2-5x-6)
I have tried doing:
x = √(y^2-5y-6)
x^2 = y^2-5y-6.......and couldn't isolate y from here.
Thank-you for your time!
Found 2 solutions by MathLover1, josgarithmetic:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

use quadratic formula; note that ,, and

or

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The roles of domain and range are switched from function to inverse.
Your given functional-form equation to start with is the upper half of a parabola with a horizontal symmetry axis.
Try completing-the-square to have a better understanding of your given parabola.

Now, what you are starting with is .
The vertex for this given equation is (5/2,-49/4).
The shape is horizontal parabola.
DOMAIN: x values must be greater than 5/2.
RANGE: y values are greater than or equal to -49/4.

If you want to now use the simple method of just switching x and y roles in the given equation, you can; and just solve that for y; and remember you must choose the RIGHT-HAND branch of the function.
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SOLUTION: Find the inverse function of y = &#8730;(x^2-5x-6) I have tried doing: x = &#8730;(y^2-5y-6) x^2 = y^2-5y-6.......and couldn't isolate y from here. Thank-you for your time!

SOLUTION: Find the inverse function of y = √(x^2-5x-6) I have tried doing: x = √(y^2-5y-6) x^2 = y^2-5y-6.......and couldn't isolate y from here. Thank-you for your time!