SOLUTION: Factor completely -53x^2+x^4+196 and also another Question factor completely 7x^2-7
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Question 908699: Factor completely -53x^2+x^4+196 and also another Question factor completely 7x^2-7
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
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Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
and substitute:
Note: 
and \ =\ -53)
, hence
(u\ -\ 49))
Substitute back
(x^2\ -\ 49))
Each of the two binomial factors is the difference of two squares which you should be able to factor for yourself.
John
My calculator said it, I believe it, that settles it
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