SOLUTION: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t − 16t^2 . The maximum height that the ball reaches is ___

SOLUTION: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t − 16t^2 . The maximum height that the ball reaches is ____

Question 906420: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t − 16t^2 .
The maximum height that the ball reaches is ____ feet
The ball reaches its maximum height when t = ____ seconds.
The ball hits the ground ____ seconds after it was thrown.
What is the average rate of change in the ball's height from t = a to t = a + h? (Don't forget to simplify Average rate of change = ____ feet/second
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
h(t) = 24t − 16t^2
-32t+24=0
4t=3
t=.75 sec at max h(t)=9 ft
0= 24t − 16t^2
24t = 16t^2
3t=2t^2
3=2t
t=3/2 when it hits the ground

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SOLUTION: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t &#8722; 16t^2 . The maximum height that the ball reaches is ____

SOLUTION: If a ball is thrown upward with a speed of 24 feet per second, then t seconds later its height h is h(t) = 24t − 16t^2 . The maximum height that the ball reaches is ____