SOLUTION: Here's the problem: If there are originally 25 bacteria, at what rate are they growing if the population of the bacteria doubles in 5 hours? (Hint:solve 50=25(1+r)^5)

Question 893085: Here's the problem: If there are originally 25 bacteria, at what rate are they growing if the population of the bacteria doubles in 5 hours? (Hint:solve 50=25(1+r)^5)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
You can solve the given equation, which seems to be based on hourly rate of increase r every hour.

Evaluating the right side in base ten,

r=0.15, meaning rate is 15% each hour.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Here's the problem: If there are originally 25 bacteria, at what rate are they growing if the population of the bacteria doubles in 5 hours? (Hint:solve 50=25(1+r)^5)

------ Dividing both sides by 25
------ Raising each side to reciprocal of exponent, 5, or

r, or growth rate = .148698355, or rounded to: %
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