SOLUTION: please explain to me:Find the Natural domains of p(x)= 1/x^2-5x+6
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Question 889942: please explain to me:Find the Natural domains of p(x)= 1/x^2-5x+6
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
p(x) = 1 / (x^2 -5x +6)
factor the denominator
p(x) = 1 / (x-6)*(x+1)
therefore the natural domain of p(x) is all real numbers EXCEPT x = 6 and x = -1
since division by 0 is not defined.
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