SOLUTION: an object that is projected straight downward with initial velocity, v feet per second travels a distance s=vt+16t^2 where t= time in seconds. If ramon is standing on a balcony 84

Question 889367: an object that is projected straight downward with initial velocity, v feet per second travels a distance s=vt+16t^2 where t= time in seconds. If ramon is standing on a balcony 84 feet above the ground and throws a penny straight down with an initial velocity of 10 feet per second, in how many seconds will it reach the ground
A. 2 seconds
B. 3 seconds
C. 6 seconds
D. 8 seconds
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
an object that is projected straight downward with initial velocity, v feet per second travels a distance s=vt+16t^2 where t= time in seconds. If ramon is standing on a balcony 84 feet above the ground and throws a penny straight down with an initial velocity of 10 feet per second, in how many seconds will it reach the ground
***
s=vt+16t^2
84=10t+16t^2
16t^2+10t-84=0
(t-2)(16t+42)=0
t=-42/16 (reject)
or
t=2
in how many seconds will the object reach the ground? 2 (ans. A.)
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