Question 885298: find dy/dx
x=t^2
y=square root of t^3
dx/dt= 2t
dy/dt=square root of 3t^2
dy/dx= square root of 3t^2/2t (which is wrong, why?)
x=t^2+5t
y=t/5
dx/dt=2t+5
dy/dt=t5^-1 =-5^-2t
dy/dx=(-5^-2)/(2t+5) which is of course, wrong again. please tutor, tell me what i am doing wrong!
thank you Answer by josgarithmetic(39617) (Show Source):