SOLUTION: With f(x)=x^2-8x-1, find all values of x for which f(x)=0.

Question 881939: With f(x)=x^2-8x-1, find all values of x for which f(x)=0.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
f(x)=x^2-8x-1
x^2 - 8x - 1+ 0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=68 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 8.12310562561766, -0.123105625617661. Here's your graph:

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