SOLUTION: For this function, calculate the equation of the tangent line at the given point f(x) = tan x + (x^2/ pie^2) at the point (pie,1)

Question 852167: For this function, calculate the equation of the tangent line at the given point
f(x) = tan x + (x^2/ pie^2) at the point (pie,1)

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
For this function, calculate the equation of the tangent line at the given point
f(x) = tan x + (x^2/ pie^2) at the point (pie,1)
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I'll use the Greek letter pi, not the dessert, pie.
------
f(x) = tan x + (x^2/ pi^2) at the point (pi,1)
f'(x) = sec^2(x) + 2x/pi^2
f'(pi) = 1 + 2pi/pi^2
= 1 + 2/pi
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y - 1 = (1 + 2/pi)*(x - pi)
y = 1 + x - pi + 2x/pi - 2

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