SOLUTION: f(x)=x^2-bx I am trying to figure out the algebraic definition of "f" reflected over the y-axis, this is what I have:
f(-x)=(-x)^2-(-bx)
f(-x)=x^2-bx
I am not sure if I have
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-> SOLUTION: f(x)=x^2-bx I am trying to figure out the algebraic definition of "f" reflected over the y-axis, this is what I have:
f(-x)=(-x)^2-(-bx)
f(-x)=x^2-bx
I am not sure if I have
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Question 839754: f(x)=x^2-bx I am trying to figure out the algebraic definition of "f" reflected over the y-axis, this is what I have:
f(-x)=(-x)^2-(-bx)
f(-x)=x^2-bx
I am not sure if I have figured this out right. Answer by Fombitz(32388) (Show Source):
