SOLUTION: What is the domain of h(x)= 4x^(3/5) - x^(8/5)? When i solved for it i got all real numbers, but wolfram said x must be greater or equal to 0.

Question 819427: What is the domain of h(x)= 4x^(3/5) - x^(8/5)?
When i solved for it i got all real numbers, but wolfram said x must be greater or equal to 0.
Found 2 solutions by stanbon, TimothyLamb:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the domain of h(x)= 4x^(3/5) - x^(8/5)?
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Because x is a base in each term, it cannot be negative
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Cheers,
Stan H.
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Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
f(x) = 4x^(3/5) - x^(8/5)
f(x) = 4(x^3)^(1/5) - (x^8)^(1/5)
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the (x^3)^(1/5) term is a radical whose argument can be a negative number, for example if x=-2, then (-2^3)^(1/5) is a complex number
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if you want f(x) to be a real-valued function, limit your domain to x >= 0
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if you want f(x) to be a complex-valued function, your domain can be all real x
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