Hi,

the vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  

f(x)= 3x^2 + 6x +4

    = 3(x+1)^2 - 3 + 4  |Completing the Square

    = 3(x+1)^2 +1  V(-1,1), a= 3 >0 opening Up, f(x) = 1 is a minimum



 

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