SOLUTION: Find the domain (with the two restrictions)of the function:
y=(sqr(x+7))/(x-8)
(i.e. square root of x + 7 on top the fraction bar with x - 8 on bottom)
I got [-7, 8)U(8, infi
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Question 809797: Find the domain (with the two restrictions)of the function:
y=(sqr(x+7))/(x-8)
(i.e. square root of x + 7 on top the fraction bar with x - 8 on bottom)
I got [-7, 8)U(8, infinity) but home work site says it's incorrect. Puzzled!
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Here's a plot:
--------------
The domain looks like
because there can't be a square root
of a negative number in the numerator
But the point must be excluded since
the denominator can't be =
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Numerator will not be less than zero, and denominator cannot be 0.
and .
If you could view that on a number line, you may be able to give the interval notation for the domain:
[-7,8)U(8,oo)
or just as you said, [-7,8)U(8,infinity)
You did give the correct answer for the function' domain.
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