SOLUTION: The sum of the reciprocals of two consecutive odd integers is 8/15.Find the larger integer
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Question 76315: The sum of the reciprocals of two consecutive odd integers is 8/15.Find the larger integer
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
1/X+1/(X+2)=8/15
[(X+2)+X]/X(X+2)=8/15
(2X+2)/(X^2+2X)=8/15 CROSS MULTIPLY
15(2X+2)=8(X^2+2X)
30X+30=8X^2+16X
8X^2+16X-30X-30=0
8X^2-14X-30=0
2(4X^2-7X-15)=0
4X^2-7X-15=0
(X-3)(4X+5)=0
X-3=0
X=3 ANSWER.
4X+5=0
4X=-5
X=-5/4 ANSWER.
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