SOLUTION: the width of the rectangle is 6 feet less than twice the length. if it's area is 140 square feet, find the dimensions of the rectangle

Question 762455: the width of the rectangle is 6 feet less than twice the length. if it's area is 140 square feet, find the dimensions of the rectangle
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Length = x
Width = 2x - 6
Area = Length * Width
140 = x(2x - 6)
140 = 2x^2 - 6x
2x^2 - 6x - 140 = 0
Divide by 2
x^2 - 3x - 70 = 0
(x + 7)(x - 10)= 0
x = -7 (No answer)
x = 10
Length = 10ft
Width = 14ft
Hope this helps.
:-)
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