SOLUTION: If f(x)=x^2+1, find f(a+1)

Question 758410: If f(x)=x^2+1, find f(a+1)
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
f(x)=x^2+1

f(a+1)=(a+1)^2+1 ... replace ALL copies of 'x' with 'a+1'

f(a+1)=(a+1)(a+1)+1

f(a+1)=a(a+1)+1(a+1)+1

f(a+1)=a^2+a+a+1+1

f(a+1)=a^2+2a+2

So the answer is f(a+1)=a^2+2a+2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If f(x)=x^2+1, find f(a+1)
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f(a+1) = (a+1)^2 + 1 = a^2 + 2a + 2
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Cheers,
Stan H.
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