SOLUTION: Please I need your help!! Can you find the inverse of the following funtion? Log4 64=x

Algebra ->  Functions -> SOLUTION: Please I need your help!! Can you find the inverse of the following funtion? Log4 64=x      Log On


   



Question 755831: Please I need your help!! Can you find the inverse of the following funtion? Log4 64=x
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28+4%2C64+%29+=+x+
Do you have trouble reading this?
First of all, repeat over and over:
Logs are exponents
Logs are exponents
Logs are exponents . . .
--------------------
Now you can say in words:
exponent ( some base, the result ) = +x+
This is telling you that +x+ is an exponent
( some base, . . . ) tells you the base, so
looking at your problem,
+log%28+4%2C64+%29+=+x+
You can say:
+4%5Ex+ = the result
and, the result is +64+, so
+4%5Ex+=+64+
-------------
That's the inverse. If you practice reading these
log equations, I guarantee you'll get better at it.