find the range of the function given f(x)=-x^2+3x-5 ; domain={-1,3}



to find the range, we are going to substitute values of x to f(x)=-x^2+3x-5



When x = -1



      f(x)= -x^2 + 3x - 5

          = -(-1)^2 + 3(-1) - 5

          = -1 - 3 - 5

          = -9





When x = 3

     f(x)= -x^2 + 3x - 5

         = -(3)^2 + 3(3) - 5

         = -9 + 9 - 5

         = -5



Range = {-9, -5} 

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